Simplifying Polynomials: A Step-by-Step Guide

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Simplifying algebraic expressions can sometimes feel like navigating a maze, but don't worry, guys! We're here to break down the process step by step and make it super clear. In this article, we're going to tackle the expression (3x+4)(x2+7xβˆ’8)(3x+4)(x^2+7x-8). This looks a bit intimidating at first glance, but with a systematic approach, we can simplify it without any hassle. So, grab your pencils, and let's dive into the world of polynomials!

Understanding the Expression

Before we jump into the simplification, let's take a moment to understand what we're dealing with. The expression (3x+4)(x2+7xβˆ’8)(3x+4)(x^2+7x-8) is a product of two polynomials. The first polynomial, (3x+4)(3x+4), is a binomial because it has two terms. The second polynomial, (x2+7xβˆ’8)(x^2+7x-8), is a trinomial since it has three terms. To simplify this, we'll use the distributive property, which basically means we need to multiply each term in the first polynomial by each term in the second polynomial. This might sound like a lot, but we'll break it down into manageable steps. Think of it like this: we're going to distribute the 3x3x across all terms in the trinomial, and then we'll do the same with the 44. This ensures that every term gets multiplied correctly. It’s like making sure everyone at a party gets a slice of cake – no one gets left out! By understanding this fundamental principle, we can approach the simplification process with confidence and clarity. So, let’s get ready to multiply and simplify this expression together!

Step-by-Step Simplification

Okay, let's get our hands dirty and start simplifying the expression (3x+4)(x2+7xβˆ’8)(3x+4)(x^2+7x-8). As we discussed, we'll use the distributive property. This means we'll multiply each term in the binomial (3x+4)(3x+4) by each term in the trinomial (x2+7xβˆ’8)(x^2+7x-8).

First, let’s distribute 3x3x across the trinomial:

3xβˆ—(x2+7xβˆ’8)=3xβˆ—x2+3xβˆ—7xβˆ’3xβˆ—83x * (x^2 + 7x - 8) = 3x * x^2 + 3x * 7x - 3x * 8

This simplifies to:

3x3+21x2βˆ’24x3x^3 + 21x^2 - 24x

Now, let's distribute the 44 across the trinomial:

4βˆ—(x2+7xβˆ’8)=4βˆ—x2+4βˆ—7xβˆ’4βˆ—84 * (x^2 + 7x - 8) = 4 * x^2 + 4 * 7x - 4 * 8

Which simplifies to:

4x2+28xβˆ’324x^2 + 28x - 32

Great! We've now distributed both terms from the binomial across the trinomial. The next step is to combine these two resulting expressions:

(3x3+21x2βˆ’24x)+(4x2+28xβˆ’32)(3x^3 + 21x^2 - 24x) + (4x^2 + 28x - 32)

Now, we need to combine like terms. Like terms are those that have the same variable raised to the same power. In this case, we have x3x^3, x2x^2, xx, and constant terms. Let’s group them together:

3x3+(21x2+4x2)+(βˆ’24x+28x)βˆ’323x^3 + (21x^2 + 4x^2) + (-24x + 28x) - 32

Combining these like terms, we get:

3x3+25x2+4xβˆ’323x^3 + 25x^2 + 4x - 32

And there you have it! We've successfully simplified the expression. This step-by-step approach helps break down what looks like a complex problem into smaller, more manageable tasks. Remember, the key is to take it one term at a time and stay organized. Now, let's recap the process to ensure we've got it all down pat.

Combining Like Terms

Combining like terms is a crucial step in simplifying algebraic expressions, and it’s where things can get a little tricky if we're not careful. So, let’s break down this concept to make it crystal clear. Like terms are terms that have the same variable raised to the same power. For example, 3x23x^2 and 5x25x^2 are like terms because they both have x2x^2. On the other hand, 3x23x^2 and 5x5x are not like terms because one has x2x^2 and the other has xx. It’s like comparing apples and oranges – they're both fruit, but they're different!

When we combine like terms, we essentially add or subtract their coefficients (the numbers in front of the variables) while keeping the variable and its exponent the same. Let's look at the example from our simplified expression:

3x3+(21x2+4x2)+(βˆ’24x+28x)βˆ’323x^3 + (21x^2 + 4x^2) + (-24x + 28x) - 32

Here, we have the following like terms:

  • 21x221x^2 and 4x24x^2 are like terms.
  • βˆ’24x-24x and 28x28x are like terms.

To combine 21x221x^2 and 4x24x^2, we add their coefficients: 21+4=2521 + 4 = 25. So, 21x2+4x2=25x221x^2 + 4x^2 = 25x^2.

Similarly, to combine βˆ’24x-24x and 28x28x, we add their coefficients: βˆ’24+28=4-24 + 28 = 4. So, βˆ’24x+28x=4x-24x + 28x = 4x.

The term 3x33x^3 doesn’t have any like terms, so it remains as it is. The constant term βˆ’32-32 also doesn't have any like terms and stays the same.

This is why we ended up with the simplified expression:

3x3+25x2+4xβˆ’323x^3 + 25x^2 + 4x - 32

Combining like terms is all about paying close attention to the variables and their exponents. Think of it as sorting through a pile of LEGO bricks – you group the identical pieces together to make something bigger and better! By mastering this skill, you'll be able to simplify a wide range of algebraic expressions with confidence. So, remember to always look for the terms that match and then combine their coefficients. This will make your algebraic journey much smoother and more enjoyable.

Final Simplified Expression

After going through the step-by-step simplification, we've arrived at our final answer. The simplified form of the expression (3x+4)(x2+7xβˆ’8)(3x+4)(x^2+7x-8) is:

3x3+25x2+4xβˆ’323x^3 + 25x^2 + 4x - 32

This is a polynomial of degree 3 (because the highest power of xx is 3), and it’s in its simplest form because we've combined all like terms. It’s always a good idea to double-check your work to make sure you haven't missed any terms or made any arithmetic errors. One way to do this is to mentally retrace your steps, ensuring each multiplication and addition was done correctly. Another method is to substitute a simple value for xx, such as x=1x = 1, into both the original expression and the simplified expression. If both expressions yield the same result, it’s a good indication that you've simplified correctly. For instance, in our case:

Original Expression: (3(1)+4)((1)2+7(1)βˆ’8)=(7)(1+7βˆ’8)=(7)(0)=0(3(1)+4)((1)^2+7(1)-8) = (7)(1+7-8) = (7)(0) = 0

Simplified Expression: 3(1)3+25(1)2+4(1)βˆ’32=3+25+4βˆ’32=03(1)^3 + 25(1)^2 + 4(1) - 32 = 3 + 25 + 4 - 32 = 0

Since both expressions evaluate to 0 when x=1x = 1, it gives us confidence that our simplification is accurate. This final simplified expression is much easier to work with than the original, especially if we needed to perform further operations, such as solving equations or graphing the polynomial. So, mastering the art of simplification is not just about getting the right answer; it’s about making your mathematical life easier and more efficient!

Common Mistakes to Avoid

When simplifying algebraic expressions, it’s super easy to make little slips that can throw off your entire answer. So, let's talk about some common mistakes to watch out for. Knowing these pitfalls can save you a lot of headaches and ensure you're on the right track. One of the most frequent errors is with the distributive property. Remember, you need to multiply every term inside the parentheses by the term outside. Forgetting to multiply even one term can lead to an incorrect result. For example, when distributing 3x3x across (x2+7xβˆ’8)(x^2 + 7x - 8), make sure you multiply 3x3x by x2x^2, 7x7x, and βˆ’8-8. It’s like making sure everyone gets a birthday card – you can’t leave anyone out!

Another common mistake is with signs, especially when dealing with negative numbers. Be extra careful when distributing a negative term. For instance, if you have βˆ’2(xβˆ’3)-2(x - 3), you need to distribute the βˆ’2-2 to both xx and βˆ’3-3, resulting in βˆ’2x+6-2x + 6. Many people forget that multiplying two negatives gives a positive. It’s these little details that make a big difference. Also, watch out for errors when combining like terms. Remember, like terms must have the same variable raised to the same power. You can't combine x2x^2 with xx or a constant term. It’s like trying to fit a square peg in a round hole – it just doesn't work! Be methodical and double-check that you're only combining terms that truly match.

Lastly, be careful with arithmetic errors. Simple addition or multiplication mistakes can throw off your entire simplification. Always double-check your calculations, especially when dealing with larger numbers. It might sound basic, but even the best mathematicians make these kinds of mistakes sometimes. By being aware of these common pitfalls, you can significantly reduce the chances of making errors and simplify expressions with confidence. So, take your time, stay organized, and always double-check your work. Happy simplifying!

Practice Problems

Alright, now that we've covered the ins and outs of simplifying expressions, it's time to put our knowledge to the test! Practice makes perfect, and the more you work through problems, the more comfortable and confident you'll become. Let’s dive into some practice problems that will help you hone your skills.

Problem 1: Simplify the expression (2xβˆ’1)(x2+3xβˆ’4)(2x - 1)(x^2 + 3x - 4).

Problem 2: Simplify the expression (4x+2)(2x2βˆ’x+3)(4x + 2)(2x^2 - x + 3).

Problem 3: Simplify the expression (xβˆ’5)(x2+5x+25)(x - 5)(x^2 + 5x + 25).

Problem 4: Simplify the expression (3x+1)(x2βˆ’4xβˆ’2)(3x + 1)(x^2 - 4x - 2).

Problem 5: Simplify the expression (5xβˆ’2)(3x2+2xβˆ’1)(5x - 2)(3x^2 + 2x - 1).

These problems cover a range of scenarios, so tackling them will give you a solid understanding of the simplification process. Remember to follow the steps we discussed earlier: distribute each term in the first polynomial across the second polynomial, then combine like terms. Take your time, be careful with the signs, and don't rush through the calculations. To make the most of these practice problems, try solving them on your own first. Once you’ve given them a good shot, you can compare your answers with the solutions provided below to check your work. If you get stuck, don’t worry! Review the steps we discussed and try to identify where you might be going wrong. Learning from mistakes is a crucial part of the process. And remember, the more you practice, the easier it will become. So, grab a pen and paper, and let's get to work! Happy simplifying!

Solutions to Practice Problems

Okay, let's check our work and go through the solutions to the practice problems. This is a great way to reinforce what we've learned and clear up any confusion. Remember, the goal isn’t just to get the right answer, but to understand how we got there. So, grab your solutions, and let’s dive in!

Solution to Problem 1: Simplify (2xβˆ’1)(x2+3xβˆ’4)(2x - 1)(x^2 + 3x - 4).

First, distribute 2x2x: 2x(x2+3xβˆ’4)=2x3+6x2βˆ’8x2x(x^2 + 3x - 4) = 2x^3 + 6x^2 - 8x.

Next, distribute βˆ’1-1: βˆ’1(x2+3xβˆ’4)=βˆ’x2βˆ’3x+4-1(x^2 + 3x - 4) = -x^2 - 3x + 4.

Combine the two results: (2x3+6x2βˆ’8x)+(βˆ’x2βˆ’3x+4)(2x^3 + 6x^2 - 8x) + (-x^2 - 3x + 4).

Combine like terms: 2x3+(6x2βˆ’x2)+(βˆ’8xβˆ’3x)+42x^3 + (6x^2 - x^2) + (-8x - 3x) + 4.

Final simplified expression: 2x3+5x2βˆ’11x+42x^3 + 5x^2 - 11x + 4.

Solution to Problem 2: Simplify (4x+2)(2x2βˆ’x+3)(4x + 2)(2x^2 - x + 3).

First, distribute 4x4x: 4x(2x2βˆ’x+3)=8x3βˆ’4x2+12x4x(2x^2 - x + 3) = 8x^3 - 4x^2 + 12x.

Next, distribute 22: 2(2x2βˆ’x+3)=4x2βˆ’2x+62(2x^2 - x + 3) = 4x^2 - 2x + 6.

Combine the two results: (8x3βˆ’4x2+12x)+(4x2βˆ’2x+6)(8x^3 - 4x^2 + 12x) + (4x^2 - 2x + 6).

Combine like terms: 8x3+(βˆ’4x2+4x2)+(12xβˆ’2x)+68x^3 + (-4x^2 + 4x^2) + (12x - 2x) + 6.

Final simplified expression: 8x3+10x+68x^3 + 10x + 6.

Solution to Problem 3: Simplify (xβˆ’5)(x2+5x+25)(x - 5)(x^2 + 5x + 25).

First, distribute xx: x(x2+5x+25)=x3+5x2+25xx(x^2 + 5x + 25) = x^3 + 5x^2 + 25x.

Next, distribute βˆ’5-5: βˆ’5(x2+5x+25)=βˆ’5x2βˆ’25xβˆ’125-5(x^2 + 5x + 25) = -5x^2 - 25x - 125.

Combine the two results: (x3+5x2+25x)+(βˆ’5x2βˆ’25xβˆ’125)(x^3 + 5x^2 + 25x) + (-5x^2 - 25x - 125).

Combine like terms: x3+(5x2βˆ’5x2)+(25xβˆ’25x)βˆ’125x^3 + (5x^2 - 5x^2) + (25x - 25x) - 125.

Final simplified expression: x3βˆ’125x^3 - 125.

Solution to Problem 4: Simplify (3x+1)(x2βˆ’4xβˆ’2)(3x + 1)(x^2 - 4x - 2).

First, distribute 3x3x: 3x(x2βˆ’4xβˆ’2)=3x3βˆ’12x2βˆ’6x3x(x^2 - 4x - 2) = 3x^3 - 12x^2 - 6x.

Next, distribute 11: 1(x2βˆ’4xβˆ’2)=x2βˆ’4xβˆ’21(x^2 - 4x - 2) = x^2 - 4x - 2.

Combine the two results: (3x3βˆ’12x2βˆ’6x)+(x2βˆ’4xβˆ’2)(3x^3 - 12x^2 - 6x) + (x^2 - 4x - 2).

Combine like terms: 3x3+(βˆ’12x2+x2)+(βˆ’6xβˆ’4x)βˆ’23x^3 + (-12x^2 + x^2) + (-6x - 4x) - 2.

Final simplified expression: 3x3βˆ’11x2βˆ’10xβˆ’23x^3 - 11x^2 - 10x - 2.

Solution to Problem 5: Simplify (5xβˆ’2)(3x2+2xβˆ’1)(5x - 2)(3x^2 + 2x - 1).

First, distribute 5x5x: 5x(3x2+2xβˆ’1)=15x3+10x2βˆ’5x5x(3x^2 + 2x - 1) = 15x^3 + 10x^2 - 5x.

Next, distribute βˆ’2-2: βˆ’2(3x2+2xβˆ’1)=βˆ’6x2βˆ’4x+2-2(3x^2 + 2x - 1) = -6x^2 - 4x + 2.

Combine the two results: (15x3+10x2βˆ’5x)+(βˆ’6x2βˆ’4x+2)(15x^3 + 10x^2 - 5x) + (-6x^2 - 4x + 2).

Combine like terms: 15x3+(10x2βˆ’6x2)+(βˆ’5xβˆ’4x)+215x^3 + (10x^2 - 6x^2) + (-5x - 4x) + 2.

Final simplified expression: 15x3+4x2βˆ’9x+215x^3 + 4x^2 - 9x + 2.

How did you do? If you nailed all the problems, awesome job! If you made a few mistakes, that’s totally okay too. The important thing is to understand where you went wrong and learn from it. Go back and review the steps, paying close attention to any areas where you struggled. Simplifying expressions is a fundamental skill in algebra, and with practice, you'll become a pro in no time!

Conclusion

In conclusion, simplifying algebraic expressions like (3x+4)(x2+7xβˆ’8)(3x+4)(x^2+7x-8) might seem daunting at first, but by breaking it down into manageable steps, it becomes much less intimidating. We've seen how the distributive property is our best friend in these situations, allowing us to multiply each term correctly. Combining like terms is another critical skill, ensuring that our final expression is in its simplest form. Remember, like terms have the same variable raised to the same power, so keep those apples with apples and oranges with oranges!

We also talked about common mistakes to avoid, such as forgetting to distribute to every term, making sign errors, and incorrectly combining terms. Being mindful of these pitfalls can save you from unnecessary headaches and ensure you get the right answer. And, of course, practice is key. The more you work through problems, the more comfortable and confident you'll become. The practice problems we tackled provided a great opportunity to hone your skills and solidify your understanding. By reviewing the solutions and identifying any areas of confusion, you're well on your way to mastering algebraic simplification.

Simplifying expressions isn't just a mathematical exercise; it's a fundamental skill that opens doors to more advanced topics in algebra and beyond. Whether you're solving equations, graphing functions, or tackling calculus problems, the ability to simplify expressions will be invaluable. So, keep practicing, stay patient, and remember that every step you take is a step closer to mathematical mastery. You've got this!